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    PracticeAQA GCSEAQA GCSE Maths Foundation Tier Paper 2 CalculatorQuestion 21
    Medium2 marksStructured
    Ratio Proportion and Rates of Changedensitymassvolumeunits conversion

    AQA GCSE · Question 21 · Ratio Proportion and Rates of Change

    Some oil has a mass of 537 g and a density of 895 000 g/m³. Given that 1 m³ = 1000 litres, work out the volume of the oil. Give your answer in litres.

    How to approach this question

    1. Recall the formula relating density, mass, and volume: Density = Mass / Volume. 2. Rearrange the formula to find Volume: Volume = Mass / Density. 3. Substitute the given values: Volume = 537 g / 895 000 g/m³. 4. Calculate the volume in m³: Volume = 0.0006 m³. 5. The question asks for the answer in litres. Use the conversion factor 1 m³ = 1000 litres. 6. Convert the volume to litres: 0.0006 m³ * 1000 litres/m³ = 0.6 litres.

    Full Answer

    Step 1: Find the volume in cubic metres (m³). The formula triangle for density, mass, and volume is: Density = Mass / Volume To find the volume, we rearrange the formula: Volume = Mass / Density Given values: Mass = 537 g Density = 895 000 g/m³ Volume (in m³) = 537 / 895 000 Volume = 0.0006 m³ Step 2: Convert the volume from m³ to litres. We are given the conversion factor: 1 m³ = 1000 litres. To convert from m³ to litres, we multiply by 1000. Volume (in litres) = 0.0006 × 1000 Volume = 0.6 litres.

    Common mistakes

    ✗ Using the density formula incorrectly (e.g., multiplying mass and density). ✗ Making an error in the units conversion (e.g., dividing by 1000 instead of multiplying). ✗ Forgetting to do the final conversion to litres.
    Question 20.2All questionsQuestion 22

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