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    PracticeAQA GCSEAQA GCSE Chemistry Higher Tier Paper 2Question 01.5
    Medium4 marksStructured
    Quantitative chemistryHigherquantitative chemistrymean calculationanomaly

    AQA GCSE · Question 01.5 · Quantitative chemistry

    Table 1Concentration of sodium chloride in g/dm³Trial 1Trial 2Trial 3Trial 435.234.636.433.8

    The student calculated the concentration of sodium chloride in the salt solution. Table 1 shows the results.
    The percentage by mass of sodium ions in sodium chloride is 39.3%.
    Calculate the mean concentration of sodium ions in the salt solution.

    How to approach this question

    This is a multi-step calculation. 1. First, you need to calculate the mean concentration of sodium chloride. Look at the four trial results. Is there an anomalous result that should be excluded before calculating the mean? An anomaly is a result that does not fit the pattern of the others. 2. Calculate the mean of the remaining (concordant) results. 3. The question asks for the mean concentration of *sodium ions*, not sodium chloride. Use the percentage by mass given (39.3%) to find the concentration of just the sodium ions. 4. Convert the percentage to a decimal (divide by 100) and multiply it by the mean concentration of sodium chloride. 5. Give your final answer to an appropriate number of significant figures (usually 3 s.f. in chemistry calculations unless specified otherwise).

    Full Answer

    This calculation requires careful data handling and percentage calculation. 1. **Identify Anomalies:** The results are 35.2, 34.6, 36.4, 33.8. To identify an anomaly, we look for the value that is furthest from the others. The range of the three lowest values is 35.2 - 33.8 = 1.4. The value 36.4 is 1.2 away from the next closest value (35.2). It is considered anomalous and should be excluded from the mean calculation to improve accuracy. 2. **Calculate Mean:** The mean of the concordant results is calculated: (35.2 + 34.6 + 33.8) / 3 = 103.6 / 3 = 34.533... g/dm³. This is the mean concentration of the entire sodium chloride compound. 3. **Calculate Percentage:** The question asks for the concentration of sodium ions only. We are told sodium ions make up 39.3% of the mass of sodium chloride. We need to find 39.3% of our calculated mean concentration. 39.3% of 34.533... = (39.3 / 100) * 34.533... = 0.393 * 34.533... = 13.571... g/dm³. 4. **Significant Figures:** The input data is given to 3 significant figures, so the final answer should also be rounded to 3 significant figures: 13.6 g/dm³.

    Common mistakes

    ✗ Forgetting to exclude the anomalous result (36.4) before calculating the mean. ✗ Calculating the mean correctly but forgetting to calculate the concentration of sodium ions (the final step). ✗ Errors in percentage calculation (e.g., multiplying by 39.3 instead of 0.393). ✗ Rounding the answer to the wrong number of significant figures.
    Question 01.4All questionsQuestion 02.1

    Practice the full AQA GCSE Chemistry Higher Tier Paper 2

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