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AQA GCSE · Question 08.6 · Chemical changes
Table 4 shows the results.
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<th colspan="6" style="padding: 10px; font-size: 1.2em; border-bottom: 2px solid black;">Table 4</th>
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<th colspan="4" style="border: 1px solid black; padding: 10px; background-color: #f2f2f2;">Metal sulfate solution</th>
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<td style="border: 1px solid black; padding: 10px;">Metal</td>
<td style="border: 1px solid black; padding: 10px;">A sulfate</td>
<td style="border: 1px solid black; padding: 10px;">B sulfate</td>
<td style="border: 1px solid black; padding: 10px;">C sulfate</td>
<td style="border: 1px solid black; padding: 10px;">D sulfate</td>
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<td style="border: 1px solid black; font-weight: bold; padding: 10px;">A</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
<td style="border: 1px solid black; padding: 10px;">✓</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
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<td style="border: 1px solid black; font-weight: bold; padding: 10px;">B</td>
<td style="border: 1px solid black; padding: 10px;">✓</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
<td style="border: 1px solid black; padding: 10px;">✓</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
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<td style="border: 1px solid black; font-weight: bold; padding: 10px;">C</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
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<td style="border: 1px solid black; font-weight: bold; padding: 10px;">D</td>
<td style="border: 1px solid black; padding: 10px;">✓</td>
<td style="border: 1px solid black; padding: 10px;">✓</td>
<td style="border: 1px solid black; padding: 10px;">✓</td>
<td style="border: 1px solid black; padding: 10px;">×</td>
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✓ shows that a displacement reaction took place, <br/><br/>× shows that a displacement reaction did not take place). <br/><br/>Write metals A, B, C and D in order of reactivity. <br/><br/>Give a reason for your order of reactivity.
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Most reactive: _______________
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Least reactive: _______________
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Reason: ______________________
Table 4 shows the results.
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How to approach this question
1. The rule for displacement is: a more reactive metal will displace a less reactive metal from its salt solution.\n2. The most reactive metal will have the most ticks (✓) in its row, as it can displace the most other metals.\n3. The least reactive metal will have the most crosses (×) in its row (it will have zero ticks, as it cannot displace any other metals).\n4. Count the number of ticks for each metal: A=1, B=3, C=0, D=2.\n5. Arrange the metals in order from most ticks to least ticks. This is the order of reactivity from most to least reactive.\n6. For the reason, state the rule you used (e.g., the more reactions a metal causes, the more reactive it is).
Full Answer
To determine the order of reactivity, we count how many other metals each metal can displace. A more reactive metal will displace more metals from their solutions.\n- **Metal A** displaces 1 metal (C).\n- **Metal B** displaces 3 metals (A, C, D).\n- **Metal C** displaces 0 metals.\n- **Metal D** displaces 2 metals (A, C).\n\nThe number of metals displaced corresponds to the reactivity. Therefore, the order from most reactive to least reactive is B (3 displacements) > D (2 displacements) > A (1 displacement) > C (0 displacements).\n\n**Order:** B, D, A, C.\n**Reason:** The reactivity is determined by how many other metals it can displace from a solution of their salt. Metal B is the most reactive because it caused the most displacement reactions (3), and metal C is the least reactive because it caused no displacement reactions.
Common mistakes
✗ Getting the order incorrect.\n✗ Providing an incomplete or incorrect reason.
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