Easy1 markMultiple Choice
AQA GCSE · Question 02.5 · Chemical changes
Which is the anomalous result in Table 1?
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<table border="1" cellpadding="12" cellspacing="0" style="border-collapse: collapse; font-family: Arial, sans-serif; font-size: 15px; border: 2px solid black;">
<caption style="font-weight: bold; font-size: 16px; margin-bottom: 10px;">Table 1</caption>
<tr>
<th style="border: 1px solid black; padding: 12px; text-align: left; font-weight: bold;">Trial</th>
<th style="border: 1px solid black; padding: 12px; text-align: center; font-weight: bold;">1</th>
<th style="border: 1px solid black; padding: 12px; text-align: center; font-weight: bold;">2</th>
<th style="border: 1px solid black; padding: 12px; text-align: center; font-weight: bold;">3</th>
<th style="border: 1px solid black; padding: 12px; text-align: center; font-weight: bold;">4</th>
</tr>
<tr>
<td style="border: 1px solid black; padding: 12px; font-weight: bold;">Volume of hydrochloric acid<br/>added in cm<sup>3</sup></td>
<td style="border: 1px solid black; padding: 12px; text-align: center;">24.3</td>
<td style="border: 1px solid black; padding: 12px; text-align: center;">24.5</td>
<td style="border: 1px solid black; padding: 12px; text-align: center;">28.1</td>
<td style="border: 1px solid black; padding: 12px; text-align: center;">24.4</td>
</tr>
</table>
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Which is the anomalous result in Table 1?
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Answer options:
A.
Trial 1
B.
Trial 2
C.
Trial 3
D.
Trial 4
How to approach this question
An anomalous result is one that does not fit the pattern of the other results. Look at the four volumes recorded: 24.3, 24.5, 28.1, 24.4. Identify the value that is significantly different from the others.
Full Answer
C.Trial 3✓ Correct
The results for the volume of hydrochloric acid are 24.3 cm³, 24.5 cm³, 28.1 cm³, and 24.4 cm³. The results from Trials 1, 2, and 4 are all very close to each other (concordant). The result from Trial 3 (28.1 cm³) is much higher and does not fit the pattern. Therefore, it is the anomalous result.
Common mistakes
✗ Choosing a result that is close to the others.\n✗ Calculating the mean and choosing the one furthest from it without considering the cluster.
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