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AQA GCSE · Question 02.3 · Forces
The child pushed the baby walker 2.8 m across a horizontal floor. The work done by the child was 35 J. Calculate the horizontal force the child applied to the baby walker.
The child pushed the baby walker 2.8 m across a horizontal floor. The work done by the child was 35 J. Calculate the horizontal force the child applied to the baby walker.
How to approach this question
1. Start with the equation for work done: W = Fs.
2. You need to find the force (F), so you must rearrange the equation.
3. Substitute the given values for work done (W) and distance (s) into the rearranged equation.
4. Calculate the final answer and include the correct units.
Full Answer
The relationship between work done (W), force (F), and distance (s) is given by the equation W = Fs. To find the force, we need to rearrange this equation to F = W / s.
Given values are:
W = 35 J
s = 2.8 m
Substituting these into the rearranged equation:
F = 35 / 2.8
F = 12.5 N
The horizontal force applied was 12.5 N.
Common mistakes
✗ Using the equation incorrectly without rearranging.\n✗ Making a calculation error.\n✗ Forgetting to include the units (N) in the final answer.
Practice the full AQA GCSE Physics Higher Tier Paper 2
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