Hard4 marksStructured
Ratio Proportion and Rates of ChangeHigherRatio Proportion and Rates of ChangeDirect ProportionProportionality

AQA GCSE · Question 17 · Ratio Proportion and Rates of Change

A stone falls vertically from 300 metres above ground.

  • The stone falls d metres in t seconds.
  • d is directly proportional to the square of t.
  • The stone falls 20 metres in the first 2 seconds.
    Work out the total time taken for the stone to reach the ground.

How to approach this question

1. Translate the sentence "d is directly proportional to the square of t" into a mathematical equation involving a constant of proportionality, k. 2. Use the given values (d=20, t=2) to calculate the value of k. 3. Write the specific formula for d and t using your calculated value of k. 4. The stone reaches the ground after falling 300 metres. Use this value for d in your formula. 5. Solve the resulting equation for t to find the total time.

Full Answer

The problem involves direct proportion. Step 1: Set up the proportionality equation. "d is directly proportional to the square of t" means d ∝ t². We can write this as an equation with a constant of proportionality, k: d = kt² Step 2: Find the constant k. We are given that the stone falls 20 metres (d=20) in 2 seconds (t=2). We substitute these values into our equation to find k. 20 = k * (2)² 20 = k * 4 k = 20 / 4 = 5 Step 3: Write the specific formula. Now that we know k=5, our formula is: d = 5t² Step 4: Solve for the required time. We want to find the time it takes for the stone to reach the ground, which is a fall of 300 metres (d=300). We use our formula and solve for t: 300 = 5t² Divide both sides by 5: t² = 300 / 5 t² = 60 Take the square root of both sides: t = √60 ≈ 7.746 seconds. Rounding to a suitable degree of accuracy, for example, 3 significant figures, gives 7.75 seconds.

Common mistakes

✗ Using d = kt instead of d = kt². ✗ Incorrectly calculating k. ✗ Forgetting to square root 60 at the end to find t. ✗ Setting up a linear proportion, e.g., if 20m takes 2s, then 300m takes (300/20)*2 = 30s. This is incorrect because the relationship is not linear.

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