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    PracticeAQA GCSEAQA GCSE Maths Higher Tier Paper 1 Non-CalculatorQuestion 08
    Easy3 marksStructured
    AlgebraSolving EquationsAlgebra

    AQA GCSE · Question 08 · Algebra

    Solve 7x - 22 = 4x + 29

    How to approach this question

    The goal is to isolate the variable `x`. 1. Start by moving all the terms containing `x` to one side of the equation. You can do this by subtracting the smaller `x` term (4x) from both sides. 2. Next, move all the constant terms (the numbers) to the other side of the equation. 3. Finally, divide by the coefficient of `x` to find the value of `x`.

    Full Answer

    This is a linear equation with the variable `x` on both sides. The equation is: 7x - 22 = 4x + 29 1. To group the `x` terms, we can subtract 4x from both sides: (7x - 4x) - 22 = (4x - 4x) + 29 3x - 22 = 29 2. To group the constant terms, we can add 22 to both sides: 3x - 22 + 22 = 29 + 22 3x = 51 3. To solve for `x`, we divide both sides by 3: x = 51 / 3 To calculate 51 ÷ 3, you can split 51 into 30 + 21. 30 ÷ 3 = 10 and 21 ÷ 3 = 7. So, 10 + 7 = 17. x = 17

    Common mistakes

    ✗ Making sign errors when moving terms across the equals sign. For example, subtracting 29 instead of adding 22. ✗ Incorrectly combining terms, e.g., 7x - 4x = 11x. ✗ Errors in the final division, e.g., 51/3.
    Question 07.3All questionsQuestion 09

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