Medium3 marksStructured
Ratio Proportion and Rates of Changereverse percentagespercentagesratio

AQA GCSE · Question 24 · Ratio Proportion and Rates of Change

384 000 electric cars were sold this year. This is 20% more than last year. How many were sold last year?

How to approach this question

1. "20% more than last year" means this year's sales are 100% + 20% = 120% of last year's sales. 2. Convert this percentage to a decimal multiplier: 120% = 1.20. 3. Let L be the number of cars sold last year. The equation is L * 1.20 = 384 000. 4. To find L, we need to do the reverse operation. Divide this year's sales by the multiplier. 5. L = 384 000 / 1.20. 6. Calculate the result: L = 320 000.

Full Answer

This is a reverse percentage problem. This year's sales are "20% more than last year". This means this year's sales are 100% (last year's amount) + 20% (the increase) = 120% of last year's sales. So, we can say: 120% of last year's sales = 384 000 To work with this, we convert the percentage to a decimal multiplier: 120% = 120 / 100 = 1.2 Let L be the number of cars sold last year. The equation is: L × 1.2 = 384 000 To find L, we need to divide 384 000 by 1.2: L = 384 000 / 1.2 L = 320 000 So, 320 000 electric cars were sold last year.

Common mistakes

✗ The most common mistake is to calculate 20% of 384 000 and subtract it. This is incorrect because the 20% increase was based on last year's smaller number, not this year's larger number. (384000 * 0.8 = 307200 is the wrong answer). ✗ Dividing by 1.2 incorrectly.

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