Another circuit in the game will output True if any two sensors are activated or if all three sensors are activated. This has been represented as the Boolean expression:
(W . D) + (D . L) . (W . L)
The expression contains an error.
Shade one lozenge that shows the expression with the error corrected.

The requirement is for the circuit to be True if *at least* two sensors are on. Let's break this down: - Case 1: W and D are on. (W . D) - Case 2: D and L are on. (D . L) - Case 3: W and L are on. (W . L) The circuit should be True if Case 1 OR Case 2 OR Case 3 is true. The OR operator in Boolean algebra is `+`. Therefore, the correct expression is `(W . D) + (D . L) + (W . L)`. This expression also correctly handles the case where all three (W, D, and L) are on. If all are on, then (W.D) is true, (D.L) is true, and (W.L) is true, making the whole expression true. The original expression `(W . D) + (D . L) . (W . L)` has an error because of the final `.` (AND). This would mean "(W and D are on) OR ((D and L are on) AND (W and L are on))", which is not the required logic.