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    PracticeAQA GCSEAQA GCSE Biology Foundation Tier Paper 2Question 02.4
    Medium2 marksStructured
    Homeostasis and ResponseData analysisMean calculationReaction time

    AQA GCSE · Question 02.4 · Homeostasis and Response

    Table 1: Reaction time in millisecondsTestStudent PStudent QStudent RStudent S13173103673202309293352304329031235031543333073593085328312635313Mean315307357X

    Students investigated their reaction times using a computer program. Table 1 shows the results. Calculate mean value X in Table 1.

    How to approach this question

    1. Identify the results for Student S from the table: 320, 304, 315, 308, 313. 2. To calculate the mean, first add all these values together (the sum). 3. Count the number of values (there are 5 tests). 4. Divide the sum of the values by the number of values.

    Full Answer

    The mean is calculated by summing all the data points and dividing by the number of data points. The reaction times for Student S are: 320, 304, 315, 308, and 313. Step 1: Sum the values. 320 + 304 + 315 + 308 + 313 = 1560 Step 2: Count the number of values. There are 5 values. Step 3: Divide the sum by the count. Mean (X) = 1560 / 5 = 312 milliseconds.

    Common mistakes

    ✗ Making an error in addition. ✗ Dividing by the wrong number (e.g., 4 instead of 5). ✗ Calculating the mean for the wrong student.
    Question 02.3All questionsQuestion 02.5

    Practice the full AQA GCSE Biology Foundation Tier Paper 2

    67 questions · hints · full answers · grading

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